Provision of [challenges] polymeric hair dye. [MEANS FOR SOLVING PROBLEMS formula [Formula 1] (1a) (1b) (1c) or (In the above formula, Independently of each other, B and A, represents the polymer backbone Independently of each other, X 2 and X 1 is - carbon atoms 1 alkylene of 10 - - there is no number 2 carbon atoms alkenylene of 12 - - carbon atoms 5 Cycloalkylene - 10 - the number of carbon atoms 5 to arylene 10 - - carbon atoms 5 arylene of 10 - (carbon atoms 1 alkylene of 10) - - C (O) --(CH 2 CH 2 -O) 1-5 - -C (O) O - - OCO - - N (R 1) - - CON (R 1) --(R 1) NC (O) - - O - - S - - S ( represents a linking group selected from or a direct bond (O) 2 S - - - S (O) 2 -N (R 1 R 2) O) - Independently of one another, a hydrogen atom and R 1 and R 2 or unsubstituted or unsubstituted, branched or straight chain, a polycyclic carbon uninterrupted or interrupted or monocyclic no atoms alkyl of 1 to 14 C 2 carbon atom alkenyl 14 C 6 carbon atoms aryl group of 10 C 6 carbon atoms and aryl - 10 carbon atoms alkyl of 1 to 10 or The carbon atoms 5 to represent alkyl of 10 (carbon atoms 5 to 10 aryl) groups Independently of each other, residues of the organic dyes Y 1 and Y 2 or represents a hydrogen atom Here, one represents the residue of an organic dye of at least Y 2 and Y 1 Independently of one another, An 3 and 1, An 2 An is an anion independently of one another are 1-b and A represents a number of 3 The 0 to m represents the number of 1000 The 0 to n represents the number of 1000 and The 1 to p represents the number of 1000 Here, the sum of m + n + p is 3 or more. I disclose a polymeric dye represented by). None [Selection Figure]【課題】ポリマー状毛髪染料の提供。【解決手段】式【化1】(1a) (1b)又は (1c)(上記式中、A及びBは、互いに独立して、ポリマー骨格を表わし;X1及びX2は、互いに独立して、-炭素原子数1ないし10のアルキレン-;-炭素原子数2ないし12のアルケニレン-;-炭素原子数5ないし10のシクロアルキレン-;-炭素原子数5ないし10のアリーレン-;-炭素原子数5ないし10のアリーレン-(炭素原子数1ないし10のアルキレン)-;-C(O)-;-(CH2CH2-O)1-5-;-C(O)O-;-OCO-;-N(R1)-;-CON(R1)-;-(R1)NC(O)-;-O-;-S-;-S(O)-;-S(O)2-;-S(O)2-N(R1R2);又は直接結合から選択された結合基を表わし;R1及びR2
