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Способ построения формы зубной дуги нижней челюсти при полном отсутствии постоянных зубов
专利权人:
Gosudarstvennoe byudzhetnoe obrazovatelnoe uchrezhdenie vysshego professionalnogo obrazovaniya "Volgogradskij gosudarstvennyj meditsinskij universitet Ministerstva Zdravookhraneniya RF"
发明人:
Ivanova Olga Pavlovna,Иванова Ольга Павловна,Vologina Mariya Viktorovna,Вологина Мария Викторовна,Fursik Denis Ivanovich,Фурсик Денис Иванович,Timakov Ilya Evgenevich,Тимаков Илья Евгеньевич
申请号:
RU2015149358
公开号:
RU0002613534C1
申请日:
2015.11.17
申请国别(地区):
RU
年份:
2017
代理人:
摘要:
FIELD: medicine.SUBSTANCE: following craniofacial complex parameters are measured in millimeters: the width of the nose between the protruding points on the nose wings, is equal to segment AnAn, interarticular width - the distance between the points Ko, located at the outer edge of the joint head, equal to segment KoKo, the distance between the point Ko and Spm which is the point, located in the midline in the deepest area of supramental folds, equal to segment KoSpm. Then the parameters for dental arch construction are calculated by mathematical formulas. The dental arc begins with plotting of segment AE, which is equal to the dental arch depth Dd1-7, calculated by the formula. Segment AT is plotted on the line AE prolongation. Through the obtained points E and T two straight lines - line E and line T are plotted perpendicular to AE. Two segments, equal to half of segment AT width, are plotted on line E on both sides of point E, and segment KL, equal to the dental arch width - Wd7-7 between second molars, is obtained. Segments AK and AL, equal to frontal-distal diagonal FDDd1-7, passing from frontal vestibular point to the level of locationof the second constant molars, are plotted from point A in both sides of arch. On line AE, segment AB is plotted, equal to the depth of the anterior sectionDd1-3. Two segments equal to a half of Wd3-3 width between the canines are plotted on both sides of point B perpendicular to line A, and segment CD is obtained on line AE, from point A, segment AO is plotted, equal to the difference between segments CD and AB, from point O, a circle with radius equal to segment AO is plotted, connecting points C, A, D, the straight line connects point C to point K, and point D to point L, from the middle of lines CK and DL, perpendiculars are plotted to the intersection with line T and points M and N are obtained. From point N, arc CK is plotted with radius NC, and from point M, arc DL is plotted with radius of MD. The resulting arc KCADL is t
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