I will provide a [challenge] cationic oligomeric azo dyes. Had been resolved [means] disclosure, the following equation: [Formula 1] Wherein a hydrogen atom R 1 is carbon atoms 1 or more one alkyl group of 5, carbon atoms alkoxy of 1 to 5, or a hydroxy group - is substituted by (CO) -H group carbon atoms 1 to obtain an alkyl group having 12-(CO) - carbon atoms alkyl of 1 to 5 phenyl phenyl or - carbon atom number of 1 to (wherein the phenyl moiety, or one alkyl group of 4 The carbon atoms 1 more alkyl groups of 5, carbon atoms 1 to 2 groups alkoxy groups of 5, a halogen atom, -NH, mono - carbon atoms alkylamino of 1 to 5, di - carbon atoms 1 to represent) may be substituted alkylamino group 5, 2 group -NO, the carboxy or hydroxy group, a hydrogen atom R 2. carbon atoms or C 1 to alkyl radical of 5, X is a carbon atom is C 1 to carbon atoms one or more one alkyl having 5, a hydroxy group, carbon atoms alkoxy of 1 to 5, an amino group, (which is mono-alkylene 10 - carbon atoms 1 no alkyl amino group of 5, di - carbon atoms 1 to and, or can be substituted alkyl amino group of 5, by -SH group or /, -S-S- many -O- or based on one or more .) may be interrupted by a group carbon atoms 5 to cycloalkylene group of 10 carbon atoms 5 to 12 arylene carbon atoms 5 to arylene - 12 carbon atoms 1 to 10 alkylene biphenylene group The carbon atoms 1 or more one alkyl having 5, a hydroxy group, carbon atoms alkoxy of 1 to 5, amino, mono (which, - carbon atoms alkylamino of 1 to 5, di - carbon atom number of 1 to and, or can be substituted alkylamino group 5, the -SH group or /, -O- group, the carbon atoms 1 or more one alkylene of 4, -NR . 3 - represents the) may be interrupted by -S-S- group or group, a hydrogen atom, R 3 carbon atoms alkyl of 1 to 12 C 2 carbon atom alkenyl 14ve no number 6 carbon atoms aryl group of 12 C 6 carbon atoms and aryl 12 - carbon atoms alkyl of 1 to 12 carbon atoms 1 or alkyl of 12 - C 6 carbon atoms represents an aryl group of 12, Y is an anion represen
